Řešení

M(CuO) = 79,54 g/mol

m(CuO) = 5 g

M(NaOH) = 39,99 g/mol

ρ(NaOH, 10%) = 1,1089 g/cm³

m(NaOH) = ?

V(NaOH, 10%) = ?

2 NaOH  +  CuSO₄• 5H₂O  ―›  Cu(OH)₂  +  Na₂SO₄  +  5 H₂O

Cu(OH)₂  ―›  CuO  +  H₂O

x = 50,3 g  NaOH 10%

V = 45,34 ml NaOH 10%